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Electric Motor Energy Savings & Payback Calculator

See how much you save by switching to a higher-efficiency electric motor (IE3IE4IE5). Annual energy & cost savings and simple payback.

Annual energy saving: kWh
Annual cost saving:
Simple payback: months
kWh = P · load · hours · (1/η₁ − 1/η₂)

Why efficiency class matters

A higher electric motor efficiency class (IE3/IE4/IE5) draws less electrical input for the same shaft power, so savings accrue every operating hour. For motors running many hours/year the energy cost far exceeds the purchase price over the lifetime — upgrading to IE4/IE5 typically pays back in months. DRG Motor supplies IE3/IE4/IE5 motors from 0.55 to 355 kW.

Related tools: Electric Motor Calculator · Power Factor Correction · Pump & Fan Motor Power.

Efficiency classes (illustrative, 4-pole)

ClassName≈ Efficiency (11 kW)
IE2High~89.8%
IE3Premium~91.4%
IE4Super Premium~92.6%
IE5Ultra Premium~93.3%

Values are indicative and vary with rated power and pole count; always use the nameplate/datasheet efficiency.

Frequently asked questions

Is it worth upgrading to a higher-efficiency motor?
For motors running many hours per year, yes. The energy cost over a motor's life is far greater than its purchase price, so even a few efficiency points (IE3→IE4→IE5) usually pay back the price difference within months.
What is the difference between IE3, IE4 and IE5?
They are IEC efficiency classes: IE3 (Premium), IE4 (Super Premium) and IE5 (Ultra Premium). Each higher class has lower losses and higher efficiency for the same rated power.
How is annual saving calculated?
Saving (kWh) = P · load factor · operating hours · (1/η₁ − 1/η₂). Multiply by the electricity price for the cost saving.
How is payback calculated?
Simple payback (months) = price difference of the new motor ÷ monthly cost saving. Enter the price difference in the calculator to see it.
What is the load factor?
The average fraction of rated power the motor actually delivers (0–1). A motor sized with margin often runs at 0.7–0.9 load.
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